Question

Find the distance the point p(3,4)and th origin

Answer 1

p(3,4),O(0,0)
d= root((x2-x1) ^2 +(y2-y1) ^2)
d=root((4-0)^2 +(3-0)^2)
d=root(4^2 + 3^2)
d=root(16+9)
d=root(25)
d=5 is answer obtained

Answer 2

Answer:

Distance between Point P and Point O is 5 unit.

Step-by-step explanation:

Given:

Coordinate of Point P ( 3 , 4 )

Coordinate of Origin O ( 0 , 0 )

To find: Distance between Point P and Origin O.

We use the Distance formula,

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

here, $(x_1,y_1)=(3,4)\:\:and\:\:(x_2,y_2)=(0,0)$

So, $Distance\:Between\:Points=\sqrt{(0-3)^2+(0-4)^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=\sqrt{25}=5$

Therefore, Distance between Point P and Point O is 5 unit.