Math, asked by tockhoi, 7 months ago

Find the distance the point p(3,4) and the origin.

simple question

Answers

Answered by MaheswariS
0

\textbf{Given:}

\textsf{Points are (3,4) and (0,0)}

\textbf{To find:}

\textsf{The distance between (3,4) and (0,0)}

\textbf{Solution:}

\textbf{Formula used:}

\boxed{\begin{minipage}{7cm}$\underline{\textsf{Distance formula:}}\\\\\mathsf{The\;distance\;between\;(x_1,y_1)\;and\;(x_2,y_2)\;is}\\\\\mathsf{d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}$\end{minipage}}

\textsf{By using distance formula,}

\textsf{The distance between (3,4) and (0,0)}

\mathsf{=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}}

\mathsf{=\sqrt{(3-0)^2+(4-0)^2}}

\mathsf{=\sqrt{3^2+4^2}}

\mathsf{=\sqrt{9+16}}

\mathsf{=\sqrt{25}}

\mathsf{=5\;units}

\therefore\textsf{The distance between (3,4) and (0,0) is 5 units}

\textbf{Find more:}

The distance between the points P(-6 , 7) and Q(-1 , -5) is- * 1 point 14 units 12 units 13 units 11 units

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