Find the distance traveled by a particle in the last 1 second if moving upwards (g=10m/s)
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Answer:
5m
Explanation:
- u=10
- from 2nd law of motion u can find distance
- v=u+gt
- 0=u+ (-10)×1
- 10=u
- h=ut+½gt²
- h=10×1+½×(-10)×1²
- h= 10-5
- h=5m
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