Question

Find the distance traveled by the car after break is applied

Answer 1

Answer:

u=25ms

−1

t=10sv=0

So, retardation a=

t

u−v

​

=2.5ms

−2

s=ut−

2

1

​

at

2

=(25×10)−(

2

1

​

×2.5×10

2

)=125