Question

Find the distance travelled by an object in 3 second if its initial velocity is 5m/s and acceleration is 12 metre per second square.​

Answer 1

Answer:

Here,

Distance(s) =?

Time(t) =3 sec

Initial velocity (u) =5m/s

Acceleration=12m/sec square

By

Explanation:

1st Motion Equation

v=u+at

v=5+12×3

v=5+36

v=41m/sec

Now,

By 3rd motion equation

2as=v^2-u^2

2×12×s=41^2-5^2

24s=1681-25

s=1656/24

s=69m

Hope it helps!