Question

Find the distance travelled by ball in 5 sec when it is thrown in upload direction with
speed 40 m/s​

Answer 1

Answer:

10m distance .. because I'm in class 7 and I don't know lol

Answer 2

Answer:- According to the equation of the motion under gravity

v  

2

−u  

2

=2gs

u=initial velocity of the ball=40m/s

v= Final velocity of the ball=0m/s

Let h be the maximum height attained by the ball

Therefore,  

0  

2

−40  

2

=2(−10)h

h=(40×40)/20=80

Therefore, total distance covered by the stone during its upward and  downward journey=80+80=160m

Net displacement during  its upward and downward journey=80+(−80)=0

Explanation:

Pls MaRK Me As Brainliest.