find the distance travelled by the train between 11.50 am and 12.30 pm from the data given below. time 11.30 12.00 12.10 12.20 12.30 kmph48.2 70 82.6 85.6 78.4
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Step-by-step explanation:
Solution 1:
I think 11:30 to 12:00 the speed was 70
1150 -1200 = 70 / 6 = 11+(2/3)
1200 - 1210 = 82.6/6=13+(4.6/6)
1210-1220=85.6/6=14+(1.5/6)
1220-1230=78.4=13+(0.4/6)
adding the kilometres up
11+2/3+13+4.6/6+14+1.5/6+13+0.4/6
51+2/3+4.6/6+1/4+4/60
51+(40+46+15+4)/60
(3060+105)/60
3165/60
52.75 kms
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