Question

Find the distance traversed by the tip of the minute hand on a clock between 2:09 P.M. and 4:39 P.M. on any given day if the length of the minute hand is 10 inches.

Answer 1

Dear Student,

◆ Answer -

50 cm

● Explanation -

First we'll need to find angle betn initial and final positions of minjte hand.

Position of minute hand is independent of hour hand, hence initial and final position of minute hand are diametrically opposite to each other.

So distance between tip of minute hand at two positions will be equal to twice of minute hand length. i.e. 2×10 = 20 inch = 50 cm.

Hence, the distance traversed by the tip of the minute hand is 50 cm.