Question

Find the distance when a car starts from rest
and accelerates 1.5 m/sv for 2os.
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Answer 1

Answer:

the answer to this question is20 * 1.5

Answer 2

Answer:

using 2nd equation of motion

s=ut + 1^2 at^2

u=0 (as car has started from rest) a=1.5m/

s^2 t=2.5s

s=1/2*1.5*(1.5)^2

s=1/2*3.375

s=1.68m