Question

Find the distance when t = 9/10 hrs and speed = 40(2/3) km/hr​

Answer 1

Answer:

229 $\times$ 10⁻⁵ m.

Step-by-step explanation:

Given that,

Time (t) = $\frac{9}{10}$ hrs

Speed (v) = $40 \times \frac{2}{3}$

To find,

The distance covered in time $\frac{9}{10}$ and speed $40 \times \frac{2}{3}$

As we know

Distance = $\frac{speed}{time}$

Before we move onto our calculations, we have to change the units of speed and time as they are not in the SI unit.

Time (t) = $\frac{9}{10}$ hrs

            = 0.9 hrs

            = 3240 secs (as 1 hr = 3600 sec)

Speed (v) = $40 \times \frac{2}{3}$

                = $\frac{80}{3}$

                = $\frac{\cancel{80}}{\cancel{3}}$

               = 26.7 km/h (approx)

               = 7.42 m/s (approx) (as 1 km/h = 0.278 m/s)

Distance = $\frac{speed}{time}$

              = $\frac{7.42}{3240}$

              = 0.00229 m

              = (or) 229 $\times$ 10⁻⁵ m