Find the distancebbetween the points ( cos35°,0) and (,cos55°)
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Answer:
1
Step-by-step explanation:
(Cos35°, 0 ) and (0,Cos55°)
Distance between two points = √(x₂ - x₁)² + (y₂ - y₁)
= √ (0 - Cos35°)² + (Cos55 - 0)²
= √Cos²35 + Cos²55
= √ [Cos (90 - 55)]² + Cos²55 [∵ Cos(90 - θ) = SInθ]
= √[Sin55]² + Cos²55
= √Sin²55° + Cos²55° [ ∵ SIn²θ + Cos²θ = 1]
= √1
= 1
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