Question

find the distince A(4,-1) ,B(7,3)​

Answer 1

Answer:

The distance between (4,-1) and (7,3) is 5 unit.

Step-by-step explanation:

Let he two cordinates A and B be (4, -1) and (7,3) respectively.

Coordinate, A = (4, -1)

Where, x1 = 4, y1 = -1

Coordinate,B=(7,3)

Where

x2 = 7, y2 = 3

We know that

Distance between AB = √{(x2 - x1)2 + (y2 - y1)2}

⇒ √(7-4)²+(3+1)²=√(3)²+(4)²

⇒ √25

⇒ 5

∴ The distance between (4,-1) and (7,3) is 5 unit.