Math, asked by Emmaus, 11 months ago

find the divisibility of 390612by 3 and 9​

Answers

Answered by Anonymous
1

Answer:

for divisibility,the sum of sum of digits,

3+9+0+6+1+2= 21

21 is divisibile by 3 hence ,390612 is divisibile by 3 ,

but 21 is not divisibile by 9 thus 390612 is not divisibile by 9.

also when 390612 is divided by 3 then the quotient is 130204

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