find the divisor when 2y^3+7y^2+7y+2 is divided by certain divisor and it. yeild the quotient as y^2+3y+2=0
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Answer:
2y+1
Step-by-step explanation:
2y³ + 7y² + 7y + 2 = (y² + 3y +2)*(divisor)
∴ divisor = (2y³ + 7y² + 7y + 2)/(y² + 3y +2)
⇒ 2y + 1
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