Question

Find the divisor when 4x³ -8x²+8x+1 is divided by a polynomial g(x) we get (2x-1) as quotient and (x+3) as remainder

Answer 1

Step-by-step explanation:

4x³-8x²+8x+1 = g(x)*(2x-1) + (x+3)

4x³-8x²+7x-2 = g(x)*(2x-1)

g(x) = 4x³-8x²+7x-2 / 2x-1

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2x-1 ✓ 4x³-8x²+7x-2 \_2x²-3x+2

-4x³+2x²

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-6x²+7x-2

+6x²-3x

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4x - 2

-4x + 2

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00

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So , g(x) is (2x²-3x+2)

Answer 2

sorry I don't know

sorry