Find the domain and range of f(x)=sq.root of (x-1).
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Step-by-step explanation:
Domain :
x - 1>=0
x>=1
[1,∞)
Range:
On substituting x=1 we get 0 as value of f(x) which is the lowest value possible and highest can go till infinite as range also goes till infinite. (No negative value would be possible as it is square root of x-1.)
So the answer for range is [0,∞]
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