Question

Find the domain and range of f(x)= sqrt(9-x^2)​

Answer 1

Answer:

The value under a square root cannot be negative, or else the solution is imaginary.

Step-by-step explanation:

So, we need 9  −  x 2  ≥ 0 , or  9 ≥  x2, so  x  ≤  3  and  x ≥  −  3, or [ −  3.3 ]. As x  takes on these values, we see that the smallest value of the range is  0 , or when  x  =  ±  3  (so √  9  −  9  =  √  0  =  0), and a max when  x  = 0 , where  y  =   √ 9  −  0  =  √  9  = 3