Find the domain and range of f(x)=?x-1?
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x+1=0x+1=0
x=−1x=-1
(−∞,−1)∪(−1,∞)-∞,-1∪-1,∞
{x|x≠−1}x|x≠-1
(−∞,1)∪(1,∞)-∞,1∪1,∞
{y|y≠1}y|y≠1
Domain: (−∞,−1)∪(−1,∞),{x|x≠−1}-∞,-1∪-1,∞,x|x≠-1
Range: (−∞,1)∪(1,∞),{y|y≠1}
Please mark it as brainiest answer .............
x=−1x=-1
(−∞,−1)∪(−1,∞)-∞,-1∪-1,∞
{x|x≠−1}x|x≠-1
(−∞,1)∪(1,∞)-∞,1∪1,∞
{y|y≠1}y|y≠1
Domain: (−∞,−1)∪(−1,∞),{x|x≠−1}-∞,-1∪-1,∞,x|x≠-1
Range: (−∞,1)∪(1,∞),{y|y≠1}
Please mark it as brainiest answer .............
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