find the domain and range of f(x)=√x+4-3/x-5
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Answer:
f(x)= x−5
For f(x) to be defined, the term under the Square-root should be greater than or equal to zero.
x−5≥0
x≥5
So, the domain is [5,∞)
Now, for x−5≥0
x−5
≥0
y≥0
So, the range is [0,∞)
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