Find the domain and range of function f(x) = √x-5/√3-x
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From the above equation
X-5 cannot be negative therefore x =>5
Also
X-3 cannot be negative and zero ( since in denominator )
Therefore x > 3
From both cases we conclude so such range exist
But there is a third case in which both numerotor and denominator is zero and both are negative
i.e (3,5]
Therefore domain is (3,5]
And range will be put [0, infinity)
You will get the range by putting 3 and 5 in the equation
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