find the domain and range of real function f(x)=√4-x^2
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DO4-x² <0
(2+x)(2-x)<0 or when
2+x<0 and 2-x<0
x<-2 and x>2
RANGE 4-x²(-2.1 ,2.1-1,2.5)
This is the top half a circle and the range is [0,2
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