Question

Find the domain and range of real function f(x)= √x^2 − 16

Answer 1

Answer:

Domain of f(x): x≤ -4 or x≥4

Range is [0,∞) or f(x)≥0

Solution:

To find the domain of the function,put the expression under the square root with the condition greater than and equal to zero.

Since we know that square root does not give real values when it was on negative values.

• So,

Domain of f(x): x≤ -4 or x≥4

Range:

To find the range,put y=f(x)

y=sqrt(x^2-16)

y^2=x^2-16

x=sqrt(y^2+16)

Domain of f(x): x≤ -4 or x≥4

Range is [0,∞) or f(x)≥0

Hope it helps

please mark it as brainliest

Answer 2

HERE IS YOUR ANSWER MATE.....;

$f(x) = \sqrt{x} {}^{2} - 16$

$= > domain = > ( - \infty , \infty )$

HOPE ITS HELPFUL.....:-)