Math, asked by satyamatari424, 11 months ago

find the domain and range of the following function

y =  \sqrt{sin \:x}

Answers

Answered by Mohanbalu
0

Step-by-step explanation:

y=√sinx

y=√1²-cosx²

y=cosx

WE KNOW that,

(1-cos)²=sin

so,

the answer is cos

Similar questions