find the domain and range of the function f(x)=1÷x+3_5
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Answer:
.
f(x)=
(x−1)(3−x)
Now,
Under square root the polynomial must be positive. The domain is obtained by solving:-
.
(x−1)(3−x)≥0
.
You can obtain the zeroes of the polynomial
.
(x−1)(3−x)=0
If
.
x−1=0
x=1
.
If
3−x=0
⇒x=3
So,
x=1,3
.
So the polynomial is solved in the external intervals.
.........
x>1,x>3
So,
..
x∈(1,+∞)
Since the function f(x) is positive, due to result of square root,
The range includes all positive real numbers x≥0
Hence, this is the answer.....
Step-by-step explanation:
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