Question

find the domain and range of the function f(x) =root 36-x^2​

Answer 1

Answer:

root 36-x^2

=>6-x^2

=>-x^2=-6

=>x^2=6

=>x=root 6

Answer 2

Answer:

Domain is  $-6 \leq x \leq 6$

Range is [-6 , 6]

Step-by-step explanation:

Given: f(x) = $\sqrt{36 - x^{2} }$

To find: domain, range

Solution:

we know, the square root is only defined when the expression under the square root is non negative.

Hence,

The function is defined: $36 - x^{2}$ $\geq 0$

=> $x^{2} \leq 36$

=> |$x^{}$| $\leq 6$

∴ $-6 \leq x^{} \leq 6$

Hence, Domain is  $-6 \leq x \leq 6$

Range is [-6 , 6] Ans

#SPJ3