Question

Find the domain and range of the function f(x) =√x^2-3x+2.​

Answer 1

Domain is the set of values of x for which the function is defined.

For the square root to be defined,

x²-3x≥0

x(x-3)≥0

Therefore, x≤0 or x≥3

Hence domain of the given function is (-∞,o]∪[3,∞)

Range is the values which come out when a given value of x is kept in the given equation. 

When x∈ (-∞,0]

f(x)∈ (-∞,f(0)]

f(x)∈ (-∞,0]

When x∈ [3,∞)

f(x)∈ [f(3),∞)

f(x)∈ [0,∞)

Hence Range of f(x)= (-∞,∞)

Answer 2

Answer:

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