Question

Find the domain and range of the function f (x)= x2 -2 / x2 - 3​

Answer 1

Answer:

$domain = set \: of \: all \: real \: numbers \\ consider \: x = real \: number \\ f(1) = \frac{(1)2 - 2}{(1)2 - 3 } = 0 \\ f(2) = \frac{(2)2 - 2}{(2)2 - 3} = \frac{4 - 2}{4 - 3} = 2 \\ f(3) = \frac{(3)2 - 2}{(3)2 - 3} = \frac{6 - 2}{6 - 3} = \frac{4}{3} \\ f(4) = \frac{(4)2 - 2}{(4)2 - 3 } = \frac{8 - 2}{8 - 3} = \frac{6}{5} \\ therefore \:$

Range = {0,2,4/3,6/5......)