Question

find the domain and range of the function y=-x^2 + 4x -3

Answer 1

Answer:

To find the range, interchange x and y, then solve for y.

x=y^2-4y-12

y^2-4y=x+12

completing the square

(y^2-4y+4)=x+12+4

(y-2)^2=x+16

Take sqrt of both sides

y-2=±√(x+16)

y=±√(x+16)+2

radican≥0

x+16≥0

x≥-16

Range of f(x):

[-16,∞)

Answer 2

Step-by-step explanation:

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