Question

find the domain and range of the real function defined by $f(x)=\frac{1}{4-x^{2} }$

Answer 1

Step-by-step explanation:

for real function,4-x²≠0

for 4-x²=0

x²=4

x= -2,2

for 4-x²≠0,x≠-2,2

therefore domain= R-{2,-2}

or,. (-∞,-2)U(2,∞)

range= R