Question

Find the domain and range of the real function f(X)=√16-x​
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Answer 1

Answer:

Step-by-step explanation:

Domain of these fuctions,$\sqrt{x}$ is $x\geq 0$

So, domain of $\sqrt{16-x}$ is $16-x\geq 0$

$x-16\leq 0$

x ∈ (-∞, 16]