Question

find the domain and range of the real function
$\sqrt{16 - x^{2} }$

•the question has no mistake
•I need an proper answer

guys help me out from this problem
please

will you?
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Answer 1

Answer:

negative quantity. 16−x2≥0or16≥x2orx2≤16

∴x≤4orx≥−4 . Domain : −4≤x≤4or[−4,4]

Range : f(x) is maximum at x=0,f(x)=4 and

f(x) is minimum at x=4,f(x)=0

Range : 0≤f(x)≤4or[0,4]

Domain : −4≤x≤4, in interval notation : [−4,4]

Range: 0≤f(x)≤4, in interval notation : [0,4]

graph{(16-x^2)^0.5 [-10, 10, -5, 5]}

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Answer 2

negative quantity. 16−x2≥0or16≥x2orx2≤16

∴x≤4orx≥−4 . Domain : −4≤x≤4or[−4,4]

Range : f(x) is maximum at x=0,f(x)=4 and

f(x) is minimum at x=4,f(x)=0

Range : 0≤f(x)≤4or[0,4]

Domain : −4≤x≤4, in interval notation : [−4,4]

Range: 0≤f(x)≤4, in interval notation : [0,4]

graph{(16-x^2)^0.5 [-10, 10, -5, 5]}

hope you like it