Question

Find the domain and range of the relation R defined on A={0,1,2,3 4,5} by R ={(x,x +3):x€A}

Answer 1

Answer:

DOMAIN OF R = SET OF FIRST ELEMENT = (0,1,2,3,4,5)

RANGE OF R = SET OF SECOND ELEMENT = (3,4,5,6,7,8)

Step-by-step explanation:

GIVEN :- A=(0,1,2,3,4,5) BY R [(X,X+3):X∈A

X IS BETWEEN 0 TO 5  

X = 0,1,2,3,4,5

X+3 = 3,4,5,6,7,8

∴ R ={(0,3), (1,4), (2,5), (3,6),  (4,7), (5,8)

DOMAIN OF R = SET OF FIRST ELEMENT = (0,1,2,3,4,5)

RANGE OF R = SET OF SECOND ELEMENT = (3,4,5,6,7,8)

Answer 2

Answer:

It is given that , a= {1,5}, b={3,7} : r=(a,b) and a-b is multiple of 4.

We have to find relation r.

Solution : Consider the following pairs

(1,3)=1 -3= -2,

(1,7) = 1- 7 = -6

(5,3) = 5 -3 =2

(5,7) = 5 - 7 = -2

As , none of the pair (1,3),(1,7), (5,3),)(5,7) satisfies the condition that a-b is multiple of 4, where a= first element of ordered pair and b= Second element of ordered pair.

So→ [r(a, b) such that a-b is multiple of 4], does not form any kind of relation from a to b.

Step-by-step explanation: