find the domain and range of the relation r={(x,y) :x+y=8 and x, y are natural numbers}
Answers
Step-by-step explanation:
Let x = { 1 , 2 , 3 }
than,
if x = 1 , y = 7
x = 2 , y = 6
x = 3 , y = 5
hence,
domain = 123
range = 567
- Domain of the relation = {1 , 2 , 3 , 4 , 5 , 6 , 7}
- Range of the relation = {1 , 2 , 3 , 4 , 5 , 6 , 7}
Given :
The relation R = {(x,y) : x + y = 8 and x , y are natural numbers}
To find :
The domain and range of the relation
Solution :
Step 1 of 3 :
Find the relation R
Here the given relation is
R = {(x,y) : x + y = 8 and x , y are natural numbers}
For x = 1 , y = 7
∴ (1,7) ∈ R
For x = 2 , y = 6
∴ (2,6) ∈ R
For x = 3 , y = 5
∴ (3,5) ∈ R
For x = 4 , y = 4
∴ (4,4) ∈ R
For x = 5 , y = 3
∴ (5,3) ∈ R
For x = 6 , y = 2
∴ (6,2) ∈ R
For x = 7 , y = 1
∴ (7,1) ∈ R
Thus the relation is given by
R = { (1,7) , (2,6) , (3,5) , (4,4) , (5,3) , (6,2) , (7,1) }
Step 2 of 3 :
Find domain of the relation
Domain of the relation
= {x : (x,y) ∈ R }
= {1 , 2 , 3 , 4 , 5 , 6 , 7}
Step 3 of 3 :
Find range of the relation
Range of the relation
= {y : (x,y) ∈ R }
= {7 , 6 , 5 , 4 , 3 , 2 , 1}
= {1 , 2 , 3 , 4 , 5 , 6 , 7}
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