Find the domain of 1/
1 - 2 sin x
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1/ 1-2sinx
1-2sinx =/ 0(=/ is not equal to)
2sinx =/ -1
Sinx =/ -1/2
We know the domain of sinx = [-1,1]
Here sinx is not defined at -1/2
Therefore domain of the expression is [-1,1] - {-π/2}
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1-2sinx =/ 0(=/ is not equal to)
2sinx =/ -1
Sinx =/ -1/2
We know the domain of sinx = [-1,1]
Here sinx is not defined at -1/2
Therefore domain of the expression is [-1,1] - {-π/2}
Hope you like it and don’t forget to mark me the brainliest
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