Find the domain of 2x^2-5x+2/(x-3)(x-5)
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Answered by
4
Given 2x^2-5x+2/(x-3)(x-5) is defined only
(x-3) (x-5) ≠0
So, (x -3) ( x -5) ≠0
x ≠ { 3, 5}
So, x ∈ ( - ∞ ,3 ) ∪ (3 ,5) ∪ (5,∞)
or
x ∈ R - {3,5}
Hope helped !^^
(x-3) (x-5) ≠0
So, (x -3) ( x -5) ≠0
x ≠ { 3, 5}
So, x ∈ ( - ∞ ,3 ) ∪ (3 ,5) ∪ (5,∞)
or
x ∈ R - {3,5}
Hope helped !^^
Answered by
0
Step-by-step explanation:
X E R - { 3 / 5 } is the answer.....
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