Question

find the domain of f (x)=√4 –√ x²/
√[x]+√2
​

Answer 1

Step-by-step explanation:

x∈R : −2≤x≤2} and

{y∈R: 0≤y≤2}

Because of the radical sign, for f(x) to be a real function, 4≥x2, that implies 2≥±x. Stated more simply, it is −2≤x≤2. The domain is therefore, [-2,2] and within this domain the Range would be [0,2]. In set builder notation {x∈R : −2≤x≤2} and

{y∈R: 0≤y≤2}