find the domain of f(x)=√sinx+√16-x^2
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ANSWER :-
IF THE VALUE OF F(X)
WHERE X = 0
THEN , THE VALUE =
f (0) = √sin0 + √16- 0^2
HENCE THE ANSWER IS 4.
IF THE VALUE OF F(X)
WHERE X = 0
THEN , THE VALUE =
f (0) = √sin0 + √16- 0^2
HENCE THE ANSWER IS 4.
rhea15:
i asked for the domain of the function
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