Question

Find the domain of f(x) =
$sin ^{ - 1} ( { - x}^{2} )$

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Answer 1

[-1,1]

Step-by-step explanation:

As we know that , range of sin⁻¹(fx) is [ -π/2 , π/2]

-π/2 ≤ sin⁻¹(x²) ≤ π/2

Taking sin both side

sin(-π/2) ≤ sin{sin⁻¹(x²)} ≤ sinπ/2

• -1 ≤ x² ≤ 1

• |x | ≤ 1

• -1 ≤ x ≤ 1

since domain of f(x) = [-1,1] Answer