find the domain of f(X)=x2-9/x-3
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domain is all real number except 3
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f ( x ) = x 2 − 9 x − 3
f(x)=x2−9x−3 is not defined for x – 3 = 0, i.e., x = 3.
∴Domain of f is R – {3}. Let y = x 2 − 9 x − 3 y=x2−9x−3 ⇒ y = x + 3 (for x ≠ 3)
∴ y will take all real values of x, except 6, when x ∈ R – {3}.
∴ Range of f = R – {6}
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