Question

find the domain of real valued function 2x²+3x+1​

Answer 1

Answer:

Step-by-step explanation:

The domain of the real-valued function f (x) = √1 - 2x + 2 sin^(-1) [(3x - 1) / 2] is (1) [-1 / 3, 1] (2) [1 / 2, 1] (3) [-1 / 2, 1 / 3] (4) [-1 / 3, 1 / 2]

Solution: (4)

√1 – 2x

1 – 2x ≥ 0

1 ≥ 2x

(1 / 2) ≥ x

-1 ≤ [(3x – 1) / 2] ≤ 1

-2 ≤ 3x – 1 ≤ 2

-1 ≤ 3x ≤ 3

(-1 / 3) ≤ (x / 2) ≤ 1

x ∈ (-∞, 1 / 2)

x ∈ [-1 / 3, 1 / 2]