Question

find the domain of square root of 4x-x^

Answer 1

Answer:

Find the domain and range of

4x−x

2

f(x)=

4x−x

2

=a

Domains:-4x−x

2

≤0

x(4−x)≤

xϵ[0,4]

⇒x

2

−4x+a

2

=0[a>0]

x=

2

4±

16−4a

2

=1±

1−a

2

⇒4−a

2

≤0

⇒aϵ[0,2]=Range

Step-by-step explanation:

#Hope you have satisfied with this answer.

Answer 2

Answer:

The \textbf{domain}domain of function \textbf{f(x)}f(x) is the set of all values for which function is defined.

we have to find domain of function : f(x) = \sqrt{4x-x^2}

4x−x

2

To define f(x),

(4x - x²) ≥ 0 [ as we know, square root is possible only of positive terms ]

x(4 - x) ≥ 0

plot in number line and use inequality concepts ,

we get, 0 ≤ x ≤ 4

hence, domain of function \in [0,4]∈[0,4]