Question

find the domain of
$f(x) = 1 \div \sqrt{1 - {x}^{2} }$
​

Answer 1

$\fcolorbox{green}{pink}{ \huge{ {Solution :}}}$

The domain of the expression is all real numbers except where the expression is undefined

The given function is

$\star \: \sf f(x) = \frac{1}{\sqrt{1 - {(x)}^{2} }}$

For domain :

$\sf \mapsto 1 - {(x)}^{2} > 0</p><p> \\ \\ \sf \mapsto - {(x)}^{2} > - 1 \\ \\ \sf \mapsto</p><p> {(x)}^{2} < 1 \\ \\ \sf \mapsto</p><p>x < ± 1$

Hence , the domain of the given function is [-1 , 1]

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Answer 2

Answer:

Step-by-step explanation:

f(X) is defined for

1-xsqaure >0

Multiply with minus sign to make xsquare positive.so the sign changes

Xsquare-1<0

(X+1)(X-1)<0

Hence a=-1 and b=1 are the two roots

Thus -1<X<1

Domain is [-1,1]