Math, asked by prince54629, 10 months ago

find the domain of

 {sin}^{ - 1} (2x + 3) + loge(3x + 5)
f(x) =  \frac{log2( x + 3)}{ {x}^{2 + }3x + 2 }

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Answered by Anonymous
12

Answer:

see the attachment

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Answered by KINGofDEVIL
4

ANSWER

ANSWER REFER TO THE ATTACHMENT

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