Question

find the domain of the function f(x)=√x-1 + √2-x​

Answer 1

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Answer:

√x - 1 + √2 - x = 0

√x - 1 + √2 - x = 0 √x - x = 1 -√2

√x - 1 + √2 - x = 0 √x - x = 1 -√2 Squaring both sides

√x - 1 + √2 - x = 0 √x - x = 1 -√2 Squaring both sidesx + x square = 1 - 2

√x - 1 + √2 - x = 0 √x - x = 1 -√2 Squaring both sidesx + x square = 1 - 2 x + x square = -1

√x - 1 + √2 - x = 0 √x - x = 1 -√2 Squaring both sidesx + x square = 1 - 2 x + x square = -1 x + x = √-1

√x - 1 + √2 - x = 0 √x - x = 1 -√2 Squaring both sidesx + x square = 1 - 2 x + x square = -1 x + x = √-1 2x = √-1

√x - 1 + √2 - x = 0 √x - x = 1 -√2 Squaring both sidesx + x square = 1 - 2 x + x square = -1 x + x = √-1 2x = √-1x = √-1/2