find the domain of the function f(x)=x^2+2x+1/x^2-8x+12
Answers
Answered by
129
Hello!
f(x) = x² + 2x + 1 / x² - 8x + 12
= (x + 1)² / x² - 2x - 6x + 12
= (x + 1)² / x.(x - 2) - 6.(x - 2)
= (x + 1)² / (x - 2).(x - 6)
In real numbers, denominator can't be zero.
Then,
(x - 2).(x - 6) ≠ 0
∴ x ≠ 2 and x ≠ 6
Hence, the domain = R - {2,6}
Cheers!
f(x) = x² + 2x + 1 / x² - 8x + 12
= (x + 1)² / x² - 2x - 6x + 12
= (x + 1)² / x.(x - 2) - 6.(x - 2)
= (x + 1)² / (x - 2).(x - 6)
In real numbers, denominator can't be zero.
Then,
(x - 2).(x - 6) ≠ 0
∴ x ≠ 2 and x ≠ 6
Hence, the domain = R - {2,6}
Cheers!
Answered by
19
Answer:
R-{2, 6}
Step-by-step explanation:
It can be seen that function f is defined for all real numbers except at x = 6 and x = 2. Hence, the domain of f is R – {2, 6}Read
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