Question

Find the domain of the function
f (x) = √x²-1
​

Answer 1

Answer:

Answer is 0

Step-by-step explanation:

We have, f(x)= 1/√(x²-1)=y(say)

Here, x²-1>0 (since dinominator is positive)

Or, -1<x<1

Or, x€ (-1,1)

Domain of f(x) is (-1,1)

Also, x={√(1+y²)}/y

So, y≠0 hence, Range of f(x) is R-{0}

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Answer 2

Answer:

Answer is 0

Step-by-step explanation:

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