Question

Find the domain of the function of a square root of a2-x2

Answer 1

the domain of the function is -a<x<a
as a^2-x^2 should be>0 (as sqaure of -ve number is imaginary)
=>x^2<a^2
=>-a<x<a

Answer 2

Answer:

$- a \leqslant x \leqslant a$

Step-by-step explanation:

To find the domain of the function

$y = \sqrt{ {a}^{2} - {x}^{2} }$

one have to find those values of x,for which y has real values.

for that;

we know square root give imaginary value for negative quantity.

Thus

${a}^{2} - {x}^{2} \geqslant 0 \\ \\ {a}^{2} \geqslant {x}^{2} \\ \\ - a \leqslant x \leqslant a$

is the range of function.

Hope it helps you.