Question

Find the domain of the function (x2+2x+1)/(x2-8x+12)
O A) R-(-2,-6)
O B) R-(2,-6)
O C) R-(-2,6)
OD) R-{2,6}​

Answer 1

Given;

$→f(x) = \frac{ {x}^{2} + 2x + 1 }{ {x}^{2} - 8x + 12 }$

$→y = \frac{ {(x + 1)}^{2} }{(x - 6)(x - 2)}$

For the function to be real,

denominator of the function should not

be 0.

Hence,

$→ (x - 6)(x -2 ) ≠0$

$→x ≠6 \: or \: 2$

Hence,

Domain of the function

= R - {2,6}