Question

Find the domain of the real value function 1/ 6x- x²-5

Answer 1

Step-by-step explanation:

multiply by 6

x-x^2-5=0

-x^2+x-5=0

multiply by. - sing

x^2-x+5=0

by formula method

X = -b+_√b^2-4ac/2a

then you get

X=1+√19i. .....where i=√-1

and X=1-√19i

domain=x

Answer 2

In this question, we have to find the domain of the real value function 1/ 6x- x²-5.

f(x) = 1/ ( 6x -x² -5)

f (x) = 1/ ( 6x -x² -5)

considering f(x) 0f the real valued function:-

                   6x -x² -5 ≠ 0

                 x² -6x +5 ≠ 0

                  x²- 5x-x +5≠0

               x ( x-5) -1 ( x-5) ≠0

                  ( x-5) ( x-1) ≠0

          ( x-5) ≠ 0,   ( x-1) ≠0

              x ≠5, x≠1

                 x ≠ 1 ,5

Ans:-  The domain of the real value function 1/ 6x- x²-5 will be( x ≠1 ,5)

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