find the domain of the real valued function f(x) =1/
Attachments:
Answers
Answered by
12
f ( x) = 1 / ( x ² - 1 ) ( x + 3 )
f(x) is not defined when
( x² - 1 )( x + 3 ) = 0
x² - 1 = 0 , x + 3 = 0 .
x = ± 1 , x = -3
Therefore Domain of the function is R - { -1 , 1 , -3 } .
x ∈ ( - ∞ , -3 ) ∪ ( -3 , -1 ) ∪ ( -1 , 1 ) ∪ ( 1 , ∞ )
f(x) is not defined when
( x² - 1 )( x + 3 ) = 0
x² - 1 = 0 , x + 3 = 0 .
x = ± 1 , x = -3
Therefore Domain of the function is R - { -1 , 1 , -3 } .
x ∈ ( - ∞ , -3 ) ∪ ( -3 , -1 ) ∪ ( -1 , 1 ) ∪ ( 1 , ∞ )
Similar questions